Respuesta :

Answer:

[tex]{ \tt{base = \sqrt{ {23}^{2} - {16}^{2} } = 16.5 \: cm}} \\ area = \frac{1}{2} \times base \times height \\ area = \frac{1}{2} \times 16.5 \times 16 \\ { \tt{area = 132 \: {cm}^{2} }}[/tex]

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