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HELP!!!! if 3.50 moles of sodium hydroxide reacts with excess lead(II) nitrate, how many moles of Pb(OH)2 are produced?

HELP if 350 moles of sodium hydroxide reacts with excess leadII nitrate how many moles of PbOH2 are produced class=

Respuesta :

Answer: 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.

Explanation:

We are given:

Moles of sodium hydroxide = 3.50 moles

The given chemical equation follows:

[tex]Pb(NO_3)_2(aq)+2NaOH(aq)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq)[/tex]

By stoichiometry of the reaction:

If 2 moles of NaOH produces 1 mole of [tex]Pb(OH)_2[/tex]

So, 3 moles of NaOH will produce = [tex]\frac{1}{2}\times 3=1.5mol[/tex] of [tex]Pb(OH)_2[/tex]

Hence, 1.5 moles of [tex]Pb(OH)_2[/tex] are produced.

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