We have a linear function y=kx+b and we know that [tex]\displaystyle\bf \left \{ {{5*1+c=2} \atop {5p+c=-2}} \right.=>\left \{ {{c=-3} \atop {5p+c=-2}} \right. => 5p-3=-2 => p=\frac{1}{5}[/tex] [tex]\displaystyle\bf Answer: \boxed{C) \quad p=\frac{1}{5} }[/tex]
