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  • 20-05-2021
  • Chemistry
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What is the [OH-] of a substance that has a pH of 11?

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580473 580473
  • 24-05-2021

Answer:

0.001 M OH-

Explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-

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