Answer: 23.92 kJ
Step-by-step explanation:
Given
Distance moved by wagon is [tex]d=1.2\ km[/tex]
Force [tex]F=22\ N[/tex] directed at an angle of [tex]25^{\circ}[/tex] above the horizontal
Only the horizontal component of the force that is, [tex]22\cos 25^{\circ}[/tex]the wagon will cause the wagon to move, while the other force is perpendicular to the wagon and thus produce zero displacements.
Work done is
[tex]W=F\cdot s\\W=22\times 1.2\times 10^3\times \cos 25\\W=23.92\ kJ[/tex]
thus, 23.92 kJ of work is done on the wagon.
