Answer:
[tex]slope \ of \ y = 2x + 5 , m_{1} = 2\\\\Let \ the \ slope \ of \ the \ new \ line \ be \ m_{2} \\Since \ the \ lines \ are \ parallel \ m_{1} \cdot m_{2} = 1\\[/tex]
[tex]That \ is \ 2 \cdot m_{2} = 1 => m_{2} = \frac{1}{2}[/tex]
Equation of line passing through (2, -4)
[tex]y-(-4)= \frac{1}{2} (x - 2)\\\\[/tex]
[tex]y+4 = \frac{1}{2} ( x - 2)\\\\2y + 8 = x - 2\\\\2y = x -10\\y = \frac{1}{2} x -5[/tex]
