Answer:
[tex]volume \ of \ cone = \frac{1}{3}\pi R^2h = \frac{1}{3} \pi 15 \cdot 15\cdot 16 = 1200\pi[/tex]
[tex]volume \ of \ frustum \ = \frac{\pi h}{3} (R^2 + Rr+ r^2) \ where \ R \ is \ the \ base \ radius \ r \ is \ the \ top \ radius\\\\[/tex]Here r is not mentioned so we will keep it as r itself.
Substituting the values of R = 15cm and h of the frustum which is 4cm.
Volume of frustum :
[tex]\frac{4\pi }{3} (15^2+ 15r + r^2)\\\\\frac{4\pi }{3} (225+ 15r + r^2)\\\\[/tex]
