Answer:
[tex]T_2=894.45K=621.30\°C[/tex]
Explanation:
Hell there!
In this case, according to the given information, it turns out possible for us to calculate the new temperature by applying the Charles' law as a directly proportional relationship between temperature and volume:
[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]
Thus, we solve for the final temperature, T2, as shown below (make sure T1 is in Kelvins):
[tex]T_2=\frac{V_2T_1}{V_1} \\\\T_2=\frac{(25+273.15)K*45L}{15L}\\\\T_2=894.45K=621.30\°C[/tex]
Regards!
