Respuesta :

JadeThib

Answer:

Now, the molar solubility of lead(II) phosphate in water is said to be equal to 6.2⋅10−12mol L−1 . This means that in one liter of water, presumably at room temperature, you can only hope to dissolve 6.2⋅10−12 moles of lead(II) phosphate.

Explanation:

Hope this helps!!

Otras preguntas