Answer: 1.480 mm/s
Explanation:
Given
Cross-sectional area [tex]A=0.80\times 10^{-6}\ m^2[/tex]
Number density(no of charges per unit volume) [tex]n=9.5\times 10^{28}\ m^{-3}[/tex]
Current [tex]I=18\ A[/tex]
We know, drift velocity is given by
[tex]\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{18}{9.5\times 10^{28}\times 1.6\times 10^{-19}\times 0.8\times 10^{-6}}\\\Rightarrow v_d=\dfrac{18\times 10^{-3}}{12.16}=1.480\ mm/s[/tex]
