julissagarcia1114 julissagarcia1114

20-03-2021
Chemistry

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Consider this reaction mechanism:
Step 1: C4H9Br C4H9+ + Br- (slow)
Step 2: C4H9+ + OH- C4H9OH (fast)
Which rate law is consistent with the mechanism?

Consider this reaction mechanism Step 1 C4H9Br C4H9 Br slow Step 2 C4H9 OH C4H9OH fast Which rate law is consistent with the mechanism class=

Respuesta :

21ahmedfa 21ahmedfa

21-03-2021

C. rate = k[C4H9Br]

The slow step is always the rate-determining step. In the slow step, C4H9Br is the only reactant and has a coefficient of 1, so it is first order in the rate law.

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