Given:
The function is:
[tex]f(x)=350(1-0.12)^x[/tex]
To find:
The initial value of the function.
Solution:
We have,
[tex]f(x)=350(1-0.12)^x[/tex]
The value of the function at x=0 is called the initial value of the function.
For x=0, we get
[tex]f(0)=350(1-0.12)^0[/tex]
[tex]f(0)=350(0.88)^0[/tex]
Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.
[tex]f(0)=350(1)[/tex]
[tex]f(0)=350[/tex]
Therefore, the initial value of the function is 350.
