Answer: There are 113 moles of O in 12.6 moles of [tex]Fe(NO_3)_3[/tex]
Explanation:
Given : moles of [tex]Fe(NO_3)_3[/tex] = 113.4
To find : moles of O = ?
1 mole of [tex]Fe(NO_3)_3[/tex] contains = 9 moles of O atoms
Thus 12.6 mole of [tex]Fe(NO_3)_3[/tex] contains = [tex]\frac{9}{1}\times 12.6=113.4[/tex] moles of O atoms
Thus there are 113 moles of O in 12.6 moles of [tex]Fe(NO_3)_3[/tex]
