Answer: 59.58 ft
Step-by-step explanation:
Given
The area of the neighbor's fence is [tex]A=887.5\ ft^2[/tex]
Suppose the length of the fence is L and the shape of the fenced area is square
So, we can write
[tex]\Rightarrow L^2=887.5\\\Rightarrow L=\sqrt{887.5}=29.79\ ft[/tex]
According to the question, Cody's fence length must be twice of neighbor's
The length of Cody's fence is [tex]=2L=2\times 29.79=59.58\ ft[/tex]
