singhblazer10
singhblazer10 singhblazer10
  • 16-03-2021
  • Mathematics
contestada

I really need this please​

I really need this please class=

Respuesta :

mathgod666 mathgod666
  • 16-03-2021

[tex](2^{\frac{1}{2}})^n=\frac{2^x}{2^{3y}}\\2^{\frac{1}{2}n}=2^{x-3y}\\\frac{n}{2}=x-3y\\n=2x-6y[/tex]

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