Answer:
b = -T²/k(k-m) + k
Step-by-step explanation:
Given the equation T =√k(k-b)(k-m), we are to make b the subject of the formula
Square both sides
T² = (√k(k-b)(k-m))²
T² = k(k-b)(k-m)
T²/k(k-m) = k-b
Rearrange
k - b = T²/k(k-m)
b - k = - T²/k(k-m)
Add j=k to both sides
b - k + k = - T²/k(k-m) + k
b = -T²/k(k-m) + k
This gives the required expression
