Answer: Area = [tex]60\sqrt{2}[/tex]
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Explanation:
The triangle on the right side is a 45-45-90 triangle
The hypotenuse is 8, so the leg length is [tex]\frac{8}{\sqrt{2}} = \frac{8\sqrt{2}}{2} = 4\sqrt{2}[/tex]
This is the height of the parallelogram. The base is 15 which is always perpendicular to the height, and vice versa.
The area of this parallelogram is therefore, [tex]\text{base*height} = 15*4\sqrt{2} = 60\sqrt{2}[/tex]
