The root-mean-square speed-vrms = 615 m/s
Further explanation
Given
O₂ molecules
T = 212 + 273 = 485 K
Required
The root-mean-square speed
Solution
Average velocities of gases can be expressed as root-mean-square averages. (V rms)
[tex]\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}[/tex]
R = gas constant, T = temperature, Mm = molar mass of the gas particles
R = 8,314 J / mol K
T = temperature
Mm = molar mass, kg / mol = 0.032 kg/mol
Input the value :
v rms = √(3x8.314 J/mol K x 485 K)/0.032
vrms = 615 m/s
