jaimayaglenn56
jaimayaglenn56 jaimayaglenn56
  • 20-01-2021
  • Physics
contestada

A large crate is pushed across the floor with an effort of 45 Newtons. The box is pushed a distance of 3.5 meters. How much work is done?

Respuesta :

Sarah06109
Sarah06109 Sarah06109
  • 20-01-2021

Answer:

[tex]\boxed {\boxed {\sf 157.5 \ Joules }}[/tex]

Explanation:

Work is equal to the product of force and distance.

[tex]W=F*d[/tex]

The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.

[tex]F= 45 \ N \\d= 3.5 \ m[/tex]

Substitute the values into the formula.

[tex]W= 45 \ N * 3.5 \ m[/tex]

Multiply.

[tex]W= 157.5 \ N*m[/tex]

  • 1 Newton meter is equal to 1 Joule
  • Our answer of 157.5 N*m equals 157.5 J

[tex]W= 157.5 \ J[/tex]

157.5 Joules of work are done on the crate.

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