emmauzoma
emmauzoma emmauzoma
  • 18-01-2021
  • Mathematics
contestada

Assume the figure below is a rhombus:
If DE=16x-3, EF=9x+11, and DF=52, find HG



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Assume the figure below is a rhombusIf DE16x3 EF9x11 and DF52 find HG class=

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sqdancefan
sqdancefan sqdancefan
  • 29-01-2021

9514 1404 393

Answer:

  HG = √165 ≈ 12.8

Step-by-step explanation:

All sides of the rhombus are the same length, so ...

  DE = EF

  16x -3 = 9x +11

  7x = 14

  x = 2

  DE = 16(2) -3 = 29

Because the diagonals bisect each other, we have ...

  HF = DF/2 = 52/2 = 26

We know side GF is 29, so ...

  HG² + HF² = GF²

  HG² = GF² -HF² = 29² -26² = 165

  HG = √165 ≈ 12.8 . . . . rounded to tenths

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