anupamanepal418 anupamanepal418

17-12-2020
Mathematics

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solve (x^3-4x)(2x^2-3x)

Respuesta :

kafleshristi2005 kafleshristi2005

17-12-2020

Answer:

= x^2 ( 2x^3- 3x^2 - 8x + 12)

Step-by-step explanation:

(x^3-4x) (2x^2-3x)

= x^3(2x^2-3x) -4x(2x^2-3x)

= 2x^5-3x^4-8x^3+12x^2

= x^2 ( 2x^3- 3x^2 - 8x + 12)

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