16-12-2020
Mathematics

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xenia168 xenia168

16-12-2020

Answer:

(A). x ≥ [tex]\frac{16}{5}[/tex] and x ≤ - [tex]\frac{3}{4}[/tex]

Step-by-step explanation:

5x - 4 ≥ 12 ⇔ 5x ≥ 16 ⇒ x ≥ [tex]\frac{16}{5}[/tex]

and

12x + 5 ≤ - 4 ⇔ 12x ≤ - 9 ⇔ 4x ≤ - 3 ⇒ x ≤ - [tex]\frac{3}{4}[/tex]

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