Kingmoney4516 Kingmoney4516
  • 20-11-2020
  • Chemistry
contestada

What volume of a 0.311 M hydrochloric acid solution is required to neutralize 13.9 mL of a 0.110 M potassium hydroxide solution?

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maacastrobr
maacastrobr maacastrobr
  • 24-11-2020

Answer:

4.9 mL

Explanation:

To answer this question we will use the following equation:

  • C₁V₁=C₂V₂

Where the subscript 1 refers to hydrochloric acid, while 2 refers to potassium hydroxide. Meaning:

  • C₁ = 0.311 M
  • V₁ = ?
  • C₂ = 0.110 M
  • V₂ = 13.9 mL

So we solve for V₁:

  • 0.311 M * V₁= 0.110 M * 13.9 mL
  • V₁ = 4.9 mL

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