jamieschoggins998
jamieschoggins998 jamieschoggins998
  • 17-11-2020
  • Mathematics
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4/5 of Peter's money is twice as much as Weimin's money. What fraction of Peter's money is Weinim's money?

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JeanaShupp
JeanaShupp JeanaShupp
  • 22-11-2020

Answer:  [tex]\dfrac25[/tex]

Step-by-step explanation:

As per given,

[tex]\dfrac45\times(\text{Peter's money})=2 (\text{Weimin's money})[/tex]

Let x= Weimin's money

Then [tex]\dfrac45\times(\text{Peter's money})=2x[/tex]

[tex]\text{Peter's money}=2x\times\dfrac54\\\\\Rightarrow\ \text{Peter's money}=\dfrac52x[/tex]

The required fraction= [tex]\dfrac{\text{Weinim's money}}{\text{Peter's money}}[/tex]

[tex]=\dfrac{x}{\dfrac{5}{2}x}=\dfrac{1}{\dfrac52}\\\\\\=\dfrac25[/tex]

Hence, Required fraction = [tex]\dfrac25[/tex]

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