mnidia340 mnidia340
  • 16-11-2020
  • Mathematics
contestada

(3x^4-12x^3-5x^2-18+8) (x+4)

Respuesta :

myanjohnson13 myanjohnson13
  • 16-11-2020

Answer:

=3x^5−53x^3−20x^2−10x−40

Step-By-Step explanation:

=(3x^4+−12x^3+−5x^2+−18+8)(x+4)

=(3x^4)(x)+(3x^4)(4)+(−12x^3)(x)+(−12x^3)(4)+(−5x^2)(x)+(−5x^2)(4)+(−18)(x)+(−18)(4)+(8)(x)+(8)(4)

=3x^5+12x^4−12x^4−48x^3−5x^3−20x^2−18x−72+8x+32

=3x^5−53x^3−20x^2−10x−40

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