Answer:
The equilibrium temperature is 45°C
Explanation:
Given;
mass of block of ice, m₁ = 10 kg
mass of water, m₂ = 10 kg
initial temperature of the ice, t₁ = 0.0°C
initial temperature of water, t₂ = 90.0°C
let the equilibrium temperature = T
Apply the principles of mixture;
Heat lost by the water = heat gained by the ice
m₂c(90 - T) = m₁c(T - 0)
m₂(90 - T) = m₁(T - 0)
10(90 - T) = 10(T)
90 - T = T
90 = 2T
T = 90 / 2
T = 45°C
Therefore, the equilibrium temperature is 45°C
