Answer: 13 units
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Work Shown:
The two given points are [tex](x_1,y_1) = (4,3)[/tex] and [tex](x_2,y_2) = (16,8)[/tex]
Use the distance formula
[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(4-16)^2+(3-8)^2}\\\\d = \sqrt{(-12)^2+(-5)^2}\\\\d = \sqrt{144+25}\\\\d = \sqrt{169}\\\\d = 13\\\\[/tex]
