sItzelevydzezea
sItzelevydzezea sItzelevydzezea
  • 20-09-2016
  • Mathematics
contestada

Find an equation of the line that bisects the acute angles formed by the lines with equations 2x+y-5=0 and 3x-2y+6=0

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antonsandiego
antonsandiego antonsandiego
  • 23-09-2016
The solving for the first one should be like this 

[tex]2x+y-5/sqrt 2^2 1^2=2x+y-5/sqrt5 [/tex]
And the next part [tex]3x-2y+6/sqrt 3^2 -2^2=3x-2y+6/sqrt13 [/tex]

After these manipulations just multiply them 
[tex] (2sqrt13-3sqrt5)x+(sqrt13+2sqrt5) y-5sqrt13-6sqrt5=0 [/tex]
And finally you need to square and simplify for the completed answer
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