heartCr8a0zieboo
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  • 20-09-2016
  • Mathematics
contestada

Find the distance between the points with polar coordinates (3, 120°) and (0.5, 49°)

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HomertheGenius
HomertheGenius HomertheGenius
  • 21-09-2016
x 1 = 3 * cos 120° = - 3 cos 60° = - 3/2 = - 1.5
y 1 = 3 * sin 120° = 3 sin 60° = 3√3 / 2 = 2.598
x 2 = 0.5 * cos 49° = 0.328
y 2 = 0.5 * sin 49° = 0.37735479
--------------------------------------------
d = [( x 2 - x 1 )² + ( y 2 - y 1 )²]^(1/2)
d = [ ( 0.328 + 1.5 )² + ( 0.37735479 - 2.598) ] ^(1/2)
d = ( 3.341584 +4.931265 )^(1/2)
Answer: The distance is :
d = 2.876256
 
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