Answer:
H₃O⁺.
Explanation:
Hello,
In this case, ionization of ethanol yields hydrogen cations and ethoxide anions as follows:
[tex]CH_3COOH+H_2O\rightleftharpoons H_3O^++CH_3COO^-[/tex]
Which is at equilibrium as ethanol is a weak acid. Thus, since the conjugate acid is formed by the outgoing H⁺ and the water, we say that the conjugate acid is then the hydroxonium ion, H₃O⁺ whereas the conjugate base is the remaining anion CH₃COO⁻.
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