Answer:
2x-y+2= 0
Step-by-step explanation:
(-5,-2)=(x1, y1)
(3, 14) =(x2, y2)
now,
slope(m)= y2-y1 / x2-x1
=14+2 / 3+5
= 16 /8
=2 units
passing point = (-5,-2) = x1,y1
now,
eqn of the line can be represented as,
y -y1 = m (x-x1)
y +2 = 2 (x +5)
y+2 = 2x +10
y = 2x+10-8
0 = 2x+2-y
2x-y+2 =0 is the required eqn
