angiecook26
angiecook26
18-09-2020
Mathematics
contestada
if h(x)=x2-5+7.
h(2)
[tex]x2[/tex]
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elsaunicorn2112
elsaunicorn2112
18-09-2020
The way to solve this is by re-writing the equation except with 2 as x.
h(x)= x^2-5+7
h(2)= 2^2-5+7
h(2)=4-5+7
h(2)=-1+7
h(2)= 6
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