Answer:
Q = 28.9 kJ
Explanation:
Given that,
Mass of Aluminium, m = 460 g
Initial temperature, [tex]T_i=15^{\circ} C[/tex]
Final temperature, [tex]T_f=85^{\circ}[/tex]
We know that the specific heat of Aluminium is 0.9 J/g°C. The heat required to raise the temperature is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=460\ g\times 0.9\ J/g^{\circ} C\times (85-15)^{\circ} C\\\\Q=28980\ J\\\\\text{or}\\\\Q=28.9\ kJ[/tex]
So, 28.9 kJ of heat is required to raise the temperature.
