Answer:
C
Step-by-step explanation:
Since the denominators are common we can express as a single fraction.
[tex]\frac{k}{k^2-9k+20}[/tex] - [tex]\frac{5}{k^2-9k+20}[/tex]
= [tex]\frac{k-5}{k^2-9k+20}[/tex] ← factorise the denominator
= [tex]\frac{k-5}{(k-5)(k-4)}[/tex] ← cancel the common factor (k - 5) on numerator/ denominator
= [tex]\frac{1}{k-4}[/tex] → C
