Answer:
x≥2
Step-by-step explanation:
First, write out the equation as you have it:
[tex]58-10x\leq20+9x[/tex]
Then, add [tex]10x[/tex] to both sides:
[tex]58-10x+10x\leq20+9x+10x\\58\leq20+19x[/tex]
Next, subtract [tex]20[/tex] from both sides:
[tex]58-20\leq20-20+19x\\38\leq19x[/tex]
Finally, divide both sides by [tex]19[/tex]:
[tex]\frac{38}{19}\leq\frac{19x}{19}\\2\leq x[/tex]
or
[tex]x\geq 2[/tex]
Therefore: the answer to this inequality/equation is: x≥2
