krelnevr krelnevr
  • 20-06-2020
  • Mathematics
contestada

what is the equation of the circle that is centred at the origin and passes through the point (-3,4)

Respuesta :

NoblePenguin
NoblePenguin NoblePenguin
  • 20-06-2020

Answer:

The correct answer is (x)² + (y)² = r².

Step-by-step explanation:

The standard equation for a circle is (x - h)² + (y - k)² = r². Since our circle is centered at the origin, or (0, 0), our values for h and k are simply 0 and 0, so there is no need to list these values within the equation.

Now, it is time to determine r, or the radius of the circle. The circle passes through the point (-3, 4), so (-3)² + (4)² = 25², so r = 25.

Therefore, your equation is x² + y² = 25.

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