Answer:
(B)[tex]9 \pi $ units squared[/tex]
Step-by-step explanation:
In circle B, AB is one of the radii; and
AB=6
Central Angle of ABC [tex]=\dfrac{\pi}{2}$ radians[/tex]
Now, Area of a Sector
[tex]\text{Area of a Sector}=\dfrac{\theta}{2\pi} \times \pi r^2 \\=\dfrac{\frac{\pi}{2}}{2\pi} \times \pi \times 6^2\\=\dfrac{\pi}{4\pi} \times \pi \times 6^2\\=\dfrac{36}{4} \times \pi \\= 9 \pi $ units squared[/tex]
