Answer: 10m/s^2
Explanation:
Given the following :
Initial Velocity(U) = 10m/s
Angle of inclination = 30°
In other to calculate the magnitude of the vector,
We need to resolve into verti AL and horizontal component.
Vertical component of a vector(Uy) = U × Sinθ
Horizontal component(Ux) = U × Cosθ
Uy = 10 × sin30 = 10 × 0.5 = 5m/s
Ux = 10 × Cos30 = 10 × 0.866 = 8.66m/s
Therefore the magnitude equals :
U = √(Uy)^2 + (Ux)^2
U = √5^2 + 8.66^2
U = √25 + 74.9956
U = √99.9956
U = 9.9997799
U = 10m/s^2
