The axis of symmetry of f(x) = 7-4x + x^2 is x = 2
How to determine the axis of symmetry?
We have:
f(x) = 7-4x + x^2
Differentiate the function
f'(x) = -4 + 2x
Set the function to 0
-4 + 2x = 0
Add 4 to both sides
2x = 4
Divide by 2
x = 2
Hence, the axis of symmetry of f(x) = 7-4x + x^2 is x = 2
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