Answer:
x=2/3 or x=0
Step-by-step explanation:
1) Let's solve by factoring
since "x" is common in both 2x^2 and 3x let's take that out
first we have to bring "3x" to the left
so
2x^2-3x
next, factor of "x"
x(2x-3)=0
to solve, divide by x on both sides:
(2x-3)=0
add 3
2x=3
divide by 2
x=3/2
or x=0(since x(2x-3)=0, logically if x=0 then this equation would make sense)
