Answer:
6.2 ohm
Explanation:
Let R1 = 5 ohm
R2= 3 ohm
R3= 2 ohm
Since R3 and R2 are parallel then net resistance R' is given by
1/R' = 1/R2 + 1/R3
1/R' = 1/3 + 1/2
1/R' = 5/6
then
R' = 6/5 = 1.2 ohm
Now R1 and R' are in series, so
R = R1 + R'
R = 5 + 1.2
R = 6.2 ohm
