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A certain television is advertised as a 41-inch TV (the diagonal length). If the width of the TV is 40 inches, how many inches tall is the TV?

Respuesta :

DGBxBigxBrain

Answer:

9 inches

Step-by-step explanation:

A^2+b^2=c^2 so

40^2+b^2=41^2

1600+b^2=1681

so b^2=81

so b=9

kesme981

Answer:

9 inches tall

Step-by-step explanation:

Use the Pythagorean theorem: you know the hypotenuse (41) and the leg (40)

[tex]a^{2} +40^{2} =41^{2}[/tex]

Solve for a:

Simplify exponents

[tex]a^2+1600=1681[/tex]

Subtract 1600 from both sides

[tex]a^2+1600-1600=1681-1600\\a^2=81[/tex]

Find the square root

[tex]\sqrt{a^2}=\sqrt{81\\} \\a=9[/tex]

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