pariss23xo pariss23xo
  • 19-10-2014
  • Mathematics
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30-6a<-3(5+7a) how do you solve this?

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mariamikayla
mariamikayla mariamikayla
  • 19-10-2014
[tex]30-6a<-3(5+7a) \\\\ 30-6a < -15-21a \\\\ -6a+21a < -15 -30 \\\\ 15a<-45 \ |:15 \\\\ a<-3 \\\\ \boxed{a=(-\infty;-3)} [/tex]
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