cutielove9375
cutielove9375
18-07-2016
Mathematics
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dalendrk
dalendrk
18-07-2016
[tex]14mi-5\frac{7}{10}mi=[(14-5)-\frac{7}{10}]mi=(9-\frac{7}{10})mi=(8+1-\frac{7}{10})mi\\\\=(8+\frac{10}{10}-\frac{7}{10})mi=(8+\frac{10-7}{10})mi=(8+\frac{3}{10})mi=\boxed{8\frac{3}{10}mi}\\\\other\ method\\\\14mi-5\frac{7}{10}mi=14mi-5.7mi=(14-5-0.7)mi\\\\=(9-0.7)mi=\boxed{8.3mi}[/tex]
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