Answer:
Step-by-step explanation:
ACB is an inscribed angle
so ∠ACB = 1/2 mAB
Hence we got
[tex]4x+4=\frac{1}{2}. 96 \\4x+4=48\\4x=44\\x=11[/tex]
Good evening
Consider O the center of the circle
since ∠ACB is an inscribed angle then
m∠AOB = 2m∠ACB
then
96 = 2(4x + 4)
4x + 4 = 48
4x = 44
thus
x = 11
_____________________________
:)
