mikebatt2003
mikebatt2003 mikebatt2003
  • 16-03-2020
  • Mathematics
contestada

Please solve and explain how. Photo attached

Please solve and explain how Photo attached class=

Respuesta :

prestonkirch
prestonkirch prestonkirch
  • 16-03-2020

Answer:

Step-by-step explanation:

[tex]\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}[/tex]

multiply by [tex]\frac{k^2-2k}{1}[/tex] on each side

[tex]2=k^2-2k-1[/tex]

add 1 on both sides [tex]3=k^2-2k[/tex]

make it equal 0

[tex]0=k^2-2k-3[/tex]

Factor

[tex](k-3)(k+1)[/tex]

answer is 3 and -1

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