The probability of not rolling factors of 2 on first die is 0.5.
The numbers on a die are 1, 2, 3, 4, 5, 6.
Among them the factors of 2 are: 2, 4, 6.
So the events of not rolling factors of 2 are = 1, 3, 5.
n(not rolling factors of 2) = 3.
n(all cases) = 6.
So the probability of not rolling factors of 2 on first die is = [tex]\frac{3}{6}=\frac{1}{2}=0.5[/tex].
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