jlgrounds2002 jlgrounds2002
  • 20-02-2020
  • Mathematics
contestada

find an expression equivalent to 1-sinx ^2/1-cosx ^2

Respuesta :

jimrgrant1 jimrgrant1
  • 20-02-2020

Answer:

cot²x

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1, then

1 - sin²x = cos²x

1 - cos²x = sin²x

Thus

[tex]\frac{1-sin^2x}{1-cos^2x}[/tex] = [tex]\frac{cos^2x}{sin^2x}[/tex] = cot²x

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