Answer:
4.8 kcal/g
Explanation:
Given that:
mass of water = 50 g = 0.05 kg
specific heat capacity of water (c)= 1 kcal/K.kg
changes in temperature ΔT = 42°C - 18°C = 24°C
Since q = mcΔT
q = 0.05 × 1 × 24
q = 1.2 kcal
∴ 0.25 g sample of pretzel give 1.2 kcal of heat
as such 1 g of the sample will give out:
[tex]\frac{1}{0.25}*1.2[/tex]
= 4.8 kcal/g
