Answer:
The change in internal energy of the heater is 0 kJ
Explanation:
∆U = Q - W
Q is quantity of heat transferred = 1 kJ
W is work done on the heater = 1 kJ
Change in internal energy (∆U) = 1 - 1 = 0 kJ
Answer:
-2 kJ.
Explanation:
Given:
∆Q = 1 kJ
W = 1 kJ
Using the first law of thermodynamics in application to conservation of energy,
∆U = ∆Q - W
Where,
∆U = change in internal energy
∆Q = heat supplied to the system
W = workdone by the system
∆U = -1 - 1
= -2 kJ.
